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| Math Central | Quandaries & Queries |
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Question from Ken, a parent: I have a roll that is 13.5 inches wide ( OD) , and is wound on a 3 inch core. the thickness of the material is 3.5 thick. |
Hi Ken,
The formula you want is in Penny's response to an earlier question. Look at it to see if this what you want. If I am correct then using the notation in her response you have $R = 13.5$ inches, $r = 3$ inches and $t = 3.5$ inches. Thus if $T$ is the length of the material on the roll then
\[L = \frac{\pi \; \left(R^2 - r^2\right)}{t} \]
Harley
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