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2 items are filed under this topic.
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i^i |
2010-11-21 |
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From trale:
Can we use e^ix=cosx+isinx for finding i^i like that: x= pi/2 =>
e^(ipi/2)=0+i then [e^(ipi/2)]^i=i^i.then we find i^i= 0,207879576....
is it true? can we give value for x for free?thank you.
Answered by Harley Weston. |
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What is i^i? |
2008-12-27 |
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From randomness:
i have learnt that 'i' is square root of -1. What is then i^i ? It baffles my maths teacher...
Answered by Robert Dawson and Penny Nom. |
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