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3 items are filed under this topic.
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a^(2^n) |
2010-10-22 |
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From Tim:
I am trying to understand a^(2^n).
The hint they give is a^(2^(n+1)) = (a^(2^n))^2
I am writing a program that will solve a^(2^n) recursively but need to
understand the power before I begin.
I am currently pursuing writing (a) x (a^(2^(n-1))) where the
(a^(2^(n-1))) would be the recursive function call a n approaches 0.
Once n is 0, the result would be multiplied by a two more times.
Anyway, explaining these powers would be appreciated. I will most likely
complete the program before the answer but I want to understand the
logic of these powers. Thank you, Tim
Answered by Stephen La Rocque. |
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Finding square roots |
2007-05-17 |
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From Chandler:
I would like an easy way to find the square root of a number.
Answered by Gabriel Potter. |
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Solving x - sin(x) = constant |
2000-12-29 |
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From Keith Roble:
If x is in radians, how do you solve for x, where: x-sin(x) = constant?
Answered by Harley Weston. |
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