







The parameterisation of of a curve 
20140401 

From Eunice: Let C be the path along the curve given by y−80=−5x2 that moves from the point (5,−45) to the point (0,80).
Find r(t) the parameterisation of C in that direction as t∈[0,5]. How am I suppose to find the parametric of both x and y?
can I let x=t, then y=5t^2+80? thanks Answered by Penny Nom. 





Dropping supplies from an airplane 
20130214 

From Claire: An airplane flying at an altitude of 3500 feet is dropping supplies to researchers on an island. The path of the plane is parallel to the ground at the time the supplies are released and the plane is traveling at a speed of 300 mph.
a) write the parametric equations that represent the path of the supplies
c)How long will it take for the supplies to reach the ground?
d) how far will the supplies travel horizontally before they land? Answered by Penny Nom. 





The parameterization of a parabola 
20120427 

From Shawna: I am having problems finding the parameterization of a parabola. The question I was given is: Find the work done if a particle moves from the points (2,4) to (1,1) along the parabola y=x^2, while subject to the vector force of F=(x^3y,xy). So how would I start with finding the parameterization of a parabola? Answered by Penny Nom. 





Parameterization of a curve 
20090110 

From stephanie: Give parameterizations r(t)=x(t)i + y(t)j for the part of the parabola y=2xx^2, from (2,0) to (0,0). Sketch the curve using arrows to show direction for increasing t.
Essentially, i want to know how to determine the direction a particle is moving in for any curve, i have a vague idea using r'(t). Also, how do i parameterize? x=? and y=?
Ans: x=2t, y=2(2t)(2t)^2 Answered by Harley Weston. 





Parameters 
20060915 

From Chase: What is the meaning of the word "parameters" when used in reference to Algebra. Answered by Penny Nom. 





The Left Side of a Parabola. 
19981020 

From Shay: Find the parametrized equation for the left half of the parabola with the equation: Y=x^24x+3 Answered by Chris Fisher. 

