12 items are filed under this topic.
   | 
   | 
   | 
   | 
   | 
 
    | 
    | 
    | 
  
   | 
    The divisors (aliquot parts) of a positive integer | 
  2019-10-31 | 
  
    | 
  From Kenneth: Is there a fast and simple method that can be used to determine the aliquot parts, whole, positive numbers that can divide into another whole, positive number? Answered by Harley Weston. | 
  
    | 
  
    | 
  
    | 
    | 
    | 
  
   | 
    Partitions into distinct parts | 
  2015-09-19 | 
  
    | 
  From Brian: Looking for a formula where I can type in a number, 17 for example, and using the numbers 1 through 17 (1, 2, 3, 4 etc....), to come up with all possible combinations, when added, that will equal 17. And each number can only be used once.  I've tried a few search engines but my computer stares at me blankly and scratches its head :-/. Answered by Chris Fisher. | 
  
    | 
  
    | 
  
    | 
    | 
    | 
  
   | 
    The integral of sqrt(x) * ln(x) | 
  2009-10-12 | 
  
    | 
  From Oana: Hi! Can you tell me please how much is : ∫ (√x * ln x) ? Answered by Penny Nom. | 
  
    | 
  
    | 
  
    | 
    | 
    | 
  
   | 
    Integration | 
  2008-10-17 | 
  
    | 
  From hazela: integration of
  
       x sinx cosnx Answered by Harley Weston. | 
  
    | 
  
    | 
  
    | 
    | 
    | 
  
   | 
    Integration by parts | 
  2008-01-30 | 
  
    | 
  From seth: hi i really dont understand integr
ation by parts. for example, the integral(t^2sintdt.  i have u=t^2 and v'=sint also u'=t^/3  v=-cost
for the formula i have uv-integralvu' dx this is all well and good but i cant get it right. Answered by Harley Weston. | 
  
    | 
  
    | 
  
    | 
    | 
    | 
  
   | 
    Integration | 
  2007-02-02 | 
  
    | 
  From Jenna: How do I integrate ( ln(x) ) / ( x^2 ) ? Answered by Penny Nom and Claude Tardif. | 
  
    | 
  
    | 
  
    | 
    | 
    | 
  
   | 
    Can one divide a circle into 4.5 parts | 
  2006-03-30 | 
  
    | 
  From Chris: If it is possible, can one divide a circle into say, 4.5 parts (with 4 equal parts and a half part)? 
            Or for that matter, for any integer, n, into n/2 parts as above?] Answered by Walter Whiteley. | 
  
    | 
  
    | 
  
    | 
    | 
    | 
  
   | 
    Integrating e^x sin(x) | 
  2003-05-03 | 
  
    | 
  From Lech: I am having trouble integrating the following expression by parts:  ex sin(x)   I used the integrator at http://www.integrals.com/ to find the solution,  ? 1/2 ex cos(x) + 1/2 ex sin(x).     This is easy to confirm by differentiation, however I am confounded as how to arrive at the answer.   Answered by Penny Nom and Claude Tardif. | 
  
    | 
  
    | 
  
    | 
    | 
    | 
  
   | 
    Dividing a circle | 
  2001-10-17 | 
  
    | 
  From Ahmeen: I am having a hard time figuring out how a circle can be divided into 11 equal parts with only 4 cut allowed? My teacher gave this to us and I still can't cut my pie into eleven equal parts with only four cuts.  Answered by Walter Whiteley. | 
  
    | 
  
    | 
  
    | 
    | 
    | 
  
   | 
    Integration by parts | 
  2001-04-09 | 
  
    | 
  From A student: how do you integrate x tan-1x dx, i know it can be done by integration by parts maybe, but i'm not sure.... Answered by Claude Tardif and Harley Weston. | 
  
    | 
  
    | 
  
    | 
    | 
    | 
  
   | 
    Two integrals | 
  2001-04-03 | 
  
    | 
  From Jim: I'm having trouble with these integrals. Can you help me out?    1)the integral of: 
   x5 arctan x dx     2)the integral of:
   2x5 + 9x4 + 19x3 + 13x2 - 5x - 25   -----------------------------------------------  dx          x4 + 4x3 + 5x2   Answered by Claude Tardif. | 
  
    | 
  
    | 
  
    | 
    | 
    | 
  
   | 
    Congruent parts of congruent figures | 
  2000-03-10 | 
  
    | 
  From Erica: Yesterday, I recieved a test problem asking to prove two line segments equal. Here is the problem as I was given it:    Given: paralleogram ABCD  AE is perpendicular to DB  CF is perpendicular to DB  Prove: AE is equal to CF     I answered the problem as follows:  . . .  Answered by Walter Whiteley. | 
  
    | 
  
    |