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	Riemann sums		2000-03-30
		From Joshua D. Parham: If n is a positive integer, then lim (1/n)[1/(1+1/n) + 1/(1+(2/n) + ... + 1/(1+n/n)] n->infinity can be expressed as the integral from 1 to 2 of 1/x dx Answered by Penny Nom.

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