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solving an equation

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Manipulating an equation 2015-06-05
From Leigh:
Hi, I'm having trouble trying to find out how the equation y=mx+b for b comes up with the answer b=y-mx. Could you please assist me with this
Answered by Penny Nom.
BEDMAS solving for X 2007-02-07
From damian:
Hi, I am having a problem understanding why when using BEDMAS the text book example of the following question has used bedmas and reduced the calculation to 4/3.

Text book formula:
X/200,000 = (X - 90,000) / 150,000
X = 4/3 * (X - 90,000)
X = 360,000


My solution: I always thought that when you do something to one side you do the same to the other. Why would the equation bring the 200,000 / 150,000 down to 4 / 3 I would think it would look something like this.
X/200,000 = (X - 90,000) / 150,000
X = 200,000*((X - 90,000) / 150,000)

Answered by Stephen La Rocque.
Solving an equation 2000-12-29
From Bob:
Would you be able to help me solve this math equation..

Solve for b, 2 [b - (q + s)] / q = s


Answered by Penny Nom.
An equation involving x to the x 2000-07-22
From Joy Peter:
I am joy, a teacher teaching Maths at the secondary level and while solving a sum came to this stage when i got xx (1 + log x) = 0, by which we can conclude that xx = 0 or 1 + log x = 0. If xx = 0, than what should be the value of x? I feel that the value of x should then be 0 (zero) but then how do I explain this to the students as we also know that anything to the power of 0 is 1 but here 0 raised to 0 is 1. If this is not defined then how do I explain this?
Answered by Penny Nom.
 
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