  Math Central - mathcentral.uregina.ca  Quandaries & Queries    Q & Q    Topic: solving an equation   start over

4 items are filed under this topic.    Page1/1            Manipulating an equation 2015-06-05 From Leigh:Hi, I'm having trouble trying to find out how the equation y=mx+b for b comes up with the answer b=y-mx. Could you please assist me with thisAnswered by Penny Nom.     BEDMAS solving for X 2007-02-07 From damian:Hi, I am having a problem understanding why when using BEDMAS the text book example of the following question has used bedmas and reduced the calculation to 4/3. Text book formula: X/200,000 = (X - 90,000) / 150,000 X = 4/3 * (X - 90,000) X = 360,000 My solution: I always thought that when you do something to one side you do the same to the other. Why would the equation bring the 200,000 / 150,000 down to 4 / 3 I would think it would look something like this. X/200,000 = (X - 90,000) / 150,000 X = 200,000*((X - 90,000) / 150,000)Answered by Stephen La Rocque.     Solving an equation 2000-12-29 From Bob:Would you be able to help me solve this math equation.. Solve for b, 2 [b - (q + s)] / q = s Answered by Penny Nom.     An equation involving x to the x 2000-07-22 From Joy Peter: I am joy, a teacher teaching Maths at the secondary level and while solving a sum came to this stage when i got xx (1 + log x) = 0, by which we can conclude that xx = 0 or 1 + log x = 0. If xx = 0, than what should be the value of x? I feel that the value of x should then be 0 (zero) but then how do I explain this to the students as we also know that anything to the power of 0 is 1 but here 0 raised to 0 is 1. If this is not defined then how do I explain this?Answered by Penny Nom.      Page1/1    Math Central is supported by the University of Regina and The Pacific Institute for the Mathematical Sciences.    about math central :: site map :: links :: notre site français