4 items are filed under this topic.








Manipulating an equation 
20150605 

From Leigh: Hi, I'm having trouble trying to find out how the equation y=mx+b for b comes up with the answer b=ymx. Could you please assist me with this Answered by Penny Nom. 





BEDMAS solving for X 
20070207 

From damian: Hi, I am having a problem understanding why when using BEDMAS the text book example of the following question has used bedmas and reduced the calculation to 4/3.
Text book formula: X/200,000 = (X  90,000) / 150,000 X = 4/3 * (X  90,000) X = 360,000
My solution: I always thought that when you do something to one side you do the same to the other. Why would the equation bring the 200,000 / 150,000 down to 4 / 3 I would think it would look something like this. X/200,000 = (X  90,000) / 150,000 X = 200,000*((X  90,000) / 150,000) Answered by Stephen La Rocque. 





Solving an equation 
20001229 

From Bob: Would you be able to help me solve this math equation.. Solve for b, 2 [b  (q + s)] / q = s Answered by Penny Nom. 





An equation involving x to the x 
20000722 

From Joy Peter: I am joy, a teacher teaching Maths at the secondary level and while solving a sum came to this stage when i got x^{x} (1 + log x) = 0, by which we can conclude that x^{x} = 0 or 1 + log x = 0. If x^{x} = 0, than what should be the value of x? I feel that the value of x should then be 0 (zero) but then how do I explain this to the students as we also know that anything to the power of 0 is 1 but here 0 raised to 0 is 1. If this is not defined then how do I explain this? Answered by Penny Nom. 


