



 
Hi Alan, Is this what you mean by a 6'x6' octagon? If so then you can use the method Stephen used in a question from Martin to show that
which in your case give
which is approximately $2 \large \frac12 $ feet. I'm not sure what angle you need. lf you need the exterior angle, angle 1 in my diagram then it's measure is $45^{o}.$ If you want the interior angle, angle 2 in my diagram then you can use my response to a question by Trish to show that the measure of this angle is $67.5^{o}.$ Write back if you need more assistance, 



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