15 items are filed under this topic.
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3 consecutive multiples of 11 |
2017-07-22 |
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From nisha: using the multiples formula shown at ypur site how can we solve finding 3 consecutive multiples of 11 whose sum is 363 Answered by Penny Nom. |
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11 golfers over five rounds |
2015-10-15 |
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From Leo: 11 golfers over five rounds. Will golf as 4-4-3. How to set it up so everyone plays at least once with each player. Answered by Victoria West. |
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Eleven guys on a fishing trip |
2014-05-13 |
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From Mark: Eleven guys are going on a fishing trip and want to rotate so everyone fishes with the other guys with the fewest number of repeats.
They want to fish in groups of two with one fishing alone for
three and a half days so will rotate seven times.
Is there a combination that works and what is it? Answered by Victoria West. |
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11 golfers going on a golf trip for 4 rounds |
2014-05-01 |
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From David: I have 11 golfers going on a golf trip for 4 rounds of golf. I want to make sure that everyone gets a chance to play with everyone at least once but not more than twice.
Also, as we are n = 11, we will be composed of 3-4-4 everyday. I am trying to ensure that as few as people as possible play in the group of 3 (golf seems to be more enjoyable for whatever reason in foursomes). i have tried 3 differemt times and can seem to figure it out. Can you assist? Answered by Victoria West. |
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Eleven golfers |
2014-03-08 |
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From Leon: I have a group of 11 golfers wanting to play 10 rounds of golf in grouping of 4,4,3 .What is the best solution so that everyone plays each other as many times as possible Answered by Victoria West. |
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Golf for 11 |
2013-08-14 |
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From Don: 2 foursomes and 1 threesome for 6 rounds of golf Answered by Victoria West and Harley Weston. |
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Division in base eleven |
2012-05-27 |
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From Zoe: How do you divide numbers that are in base 11?
For example;
9A7A6A divided by A Answered by Penny Nom. |
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11 golfers playing 4 rounds |
2009-06-14 |
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From Brian: I have 11 golfers playing 4 rounds of golf. It would be great if we could play at least once with everybody. I realize we will have 2 foursomes and 1 threesome each round...can you help? Answered by Victoria West. |
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Divisibility by 11 |
2008-07-04 |
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From Peter: For what single digit value of n is the number n53nn672 divisible by 11? Answered by Leeanne Boehm. |
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Divisibility by 7 and 11 |
2004-10-13 |
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From Tammy: I'm stuck in class in Yr 7 And I'm finding it hard on our new topic Divisibility! When I try to find out what this means on Internet sites i can not understand the used symbols like algebra and so on. I'm stuck on the divisibility rules for the number 11! Answered by Penny. |
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39 consecutive natural numbers |
2003-08-19 |
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From A student: Prove that among any 39 consecutive natural numbers it is always possible to find one whose sum of digits is divisible by 11. Answered by Penny Nom. |
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11........1 |
2002-05-29 |
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From Un eleve: Démontrer que tout nombre impair non multiple de 5 admet un multiple de la forme:11........1 Answered by Claude Tardif. |
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Dividing a circle |
2001-10-17 |
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From Ahmeen: I am having a hard time figuring out how a circle can be divided into 11 equal parts with only 4 cut allowed? My teacher gave this to us and I still can't cut my pie into eleven equal parts with only four cuts. Answered by Walter Whiteley. |
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Hendecagon |
2000-10-09 |
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From Jillian: I need an example of a object that is in the shape of a hendecagon. I know what the shape is but I cannot come up with a real life example of an object that is this shape. Answered by Chris Fisher. |
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Divisibility by 11 |
1998-10-28 |
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From Pat Duggleby: I am an upgrading instructor at a drop-in program in Regina. One of my students is taking General Math 30 through correspondence, and we have run into some confusing instructions. The section is about divisibility rules, and we did just fine up until the rule for Divisibility by 11. The statement is as follows: | If the difference between the sum of the odd-numbered digits and the sum of the even-numbered digits, counted from right to left, is divisible by 11, then the number is divisible by 11. | . . . Answered by Penny Nom. |
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