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7 golfers, a threesome and a foursome |
2013-09-04 |
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From Scott:
I'm leading a golf trip with 7 guys, and we're playing 5 rounds of golf together with a threesome and a foursome at each course..
I want to set up a schedule where each person plays at least two rounds with each of the other 6 guys.
Is that possible? I can't seem to find the right combinations.
Thanks for your help!
Answered by Victoria West. |
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14 golfers in two person teams |
2013-09-04 |
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From Stewart:
How to rotate 14 golfers in two person teams without duplication until all have been paired at least once. Play is once per week.
Answered by Victoria West. |
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A two digit number |
2013-09-04 |
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From JEFFERSON:
The sum of the digits is 6. When the digits are interchange, the new number represented is 3 time the 10 digit of the original number. Find the original number?
Answered by Penny Nom. |
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8 numbers from 80 |
2013-09-04 |
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From susan:
Out of 80 numbers how many combinations of 8 are there and what are they.
Answered by Penny Nom. |
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How many nickles do you have? |
2013-09-04 |
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From Monica:
You have 15 more dimes than nickels. If you have $2.55, how many nickels do you have?
Answered by Penny Nom. |
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Ordering crushed stone |
2013-09-03 |
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From Prakash:
Dear Sirs,
I am working in a Soft Landscaping contracting company. If I need to purchase crushed stone with the size 50-70mm for $53,429 m^2$ area, how many 20feet containers should I need to order to my suppliers? The 20foot container has internal dimensions 5,897 mm by 2,348 mm by 2,285 mm and the $53,429 m^2$ area is to be covered by 10 cm of stone.
Answered by Harley Weston. |
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The perimeter of a 1.4 acre square |
2013-08-29 |
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From Destini:
I cannot figure out what the perimeter for 1.4 acres of land
in the shape of a square. I have tried and tried and eventually
tried to use a calculator and I still can't figure it out. Can you
help me? Thanks!
Destini
Answered by Penny Nom. |
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A schedule for 18 golfers |
2013-08-29 |
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From Brian:
After searching the data base which helped me solve at least 3 other issues I have one more un answered question. I have 18 golfers split into 6 threesomes for 4 days of golf. What is my best option for a schedule mixing them all up as much as possible over the course of the 4 days
Answered by Victoria West. |
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An algebraic equation |
2013-08-28 |
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From walter:
i'm a parent helping my daughter can you do a step by step on this equation been out of school for years thanks (4w-28)+(11w+13)=180 thanks
Answered by Penny Nom. |
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More than half of the people said... |
2013-08-26 |
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From Lucy:
Hi,
The question is:
Samoa 23%
Brazil 41%
Sri Lanka 52%
Senegal 39%
Armenia 37%
Croatia 20%
Why is the following statement true for the data above: More than half of the people said they were interested in Sri Lanka. The reason I don't understand the problem is that because the percentages add up to be greater than 100%, that means that the 500 people(as stated in the question) who participated in the survey got to pick more than once. Therefore, it is not 52% out of 100% anymore.
Thanks for taking the time to answer my question.
Answered by Robert Dawson. |
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Golden Ratio |
2013-08-26 |
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From Mark:
Please Help. I'm trying to help my Child and I have no clue on this math question.
Rectangular shapes with a length to width ratio of approximately 5 to 3 are pleasing to the eye.
The ratio is know as the golden ratio. A designer can us the expression 1/3(5w) to find the
length of such a rectangle with width 6 inches.
Answered by Robert Dawson and Penny Nom. |
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More on the scheduling of 16 golfers in 4 rounds |
2013-08-26 |
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From Peter:
I see your formula for 16 players 4 rounds.
Is it possible to get the players into different groups each day.
E.G Player 1 in group 1 the first day,
Group 2 the second day,
Group 3 the third day,
Group 4 the fourth day.
Then so on through the players.
Answered by Victoria West. |
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Tesseract |
2013-08-22 |
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From Dan:
I am not a mathematician. This seems to me an intuitively simple enough problem that I very much need an answer to from someone who's mathematics are better than mine. Please help.
The question is: for a tesseract of side length = 1
what is the distance of the center of each cube from the center of the tesseract ?
I think I have calculated the distance of each vertex from the center, and of the center of each edge from the center, but the question above baffles me.
(anyone not having a clue what I am talking about can brush up here http://en.wikipedia.org/wiki/Tesseract )
Thanks in advance - Dan V
Answered by Robert Dawson. |
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Constructing a triangle |
2013-08-22 |
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From Nazrul:
The base, the difference of the angles adjoining the base and the sum of the other
two sides are given. How can I draw the triangle?
Please help me.
Answered by Chris Fisher. |
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Euclid's Parallel Postulate |
2013-08-20 |
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From Justin:
Hello there,
I was wondering is Euclid's Fifth Parallel Postulate of parallel lines never intersecting, undecidable or essentially undecidable?
Thank you so much for any help you can provide!
Answered by Robert Dawson. |
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