22 items are filed under this topic.
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A Parabolic Arch |
2020-09-21 |
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From Malen: A hotel entrance makes a parabolic arch that can be represented by the quadratic function, y= -x^2-8x+24, where y is the height of the arch and x is the distance from wall to wall in the feet. What is the distance between the two walls of the arch. Answered by Harley Weston. |
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A parabolic arch |
2020-02-06 |
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From icyy: how high is the parabolic arch of span 20 feet and height of 16 feet, at a distance 5 feet from the center?
what equation will I be going to use? thank you Answered by Penny Nom. |
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A parabolic arch |
2017-01-05 |
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From Rand: It is most likely already been answered but I can not seem to find the right key words for the search engine?.
What I am looking for is, if you have an have arch/arc and you know the degree of slope and the height of the arch/arc from ground lvl; how do you factor the decreasing angle/#’s to get the distance tween the two feet on the assumption that the arch/arc is curved all the way to ground lvl?
a. where the legs widen continuously (till they hit ground) so yes parabolic &
b. where the legs come down straight after a ½ circumference run.
What I am focusing is the parabolic.
Many Thanks Answered by Harley Weston. |
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Shooting a ball at a target |
2016-02-16 |
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From Thys: Hi
I have a problem with the formula that i use .(for programming)
I have looked all over the web to find a solution but no luck.
I have a cannon that shoots a ball at a target
I use this formula to calculate what my initial velocity must be to hit the target
at a angle of 30 degrees and a distance of 15m (the cannon and target position is known)
It works perfectly if both is at same height but if one is higher or lower it miss.
In an example I am working with the range is 30m, the angle is 45 degrees and the target is 10m higher than my position.
Please help
Formula = V0 = √RG / Sin(2α) Answered by Harley Weston. |
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The height of a parabolic arc |
2015-12-30 |
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From Tom: Is there an algebraic means to determine the highest point of a parabolic arc if the base and perimeter are known? Answered by Penny Nom. |
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A parabolic arch |
2015-11-30 |
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From Muhammad: An arch over a road has a parabolic shape it is 6 meter wide at the base and is just
tall enough to allow a truck 5 meter high and 4 meter wide to pass
a):
assuming that the arch has an equation of the form y=a(x)^2+b use the given
information to find a & b. explain why this assumption is reasonable.
b):
sketch the graph of arch equation Answered by Penny Nom. |
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The distance over a Quonset |
2015-08-20 |
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From jane: total base of hemisphere is 30 ft
apex height is 20 feet
what is total length over dome Answered by Penny Nom. |
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A parabolic arch |
2012-01-04 |
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From Swathi: A plan for an arch in the shape of a parabola is drawn on a grid with a scale of 1m per square.
The base of the arch is located at the points (0,0) and (15,0). The maximum height of the arch
is 18m.
a)Determine the quadratic function that models that arch
b)State the domain and range of the function Answered by Penny Nom. |
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Will the ball clear the tree? |
2010-11-14 |
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From MK: Sam hits a golf ball with a five-iron a distance of 120m horizontally. A tree 45m high and 35m in front of Sam is directly in the path of the ball. Will the ball clear the tree if the ball makes a parabolic curve and has a maximum height or 80m? Answered by Brennan Yaremko. |
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A parabolic arch |
2009-03-28 |
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From Jeni: A doorway is in the shape of a parabolic arch.
Find the width of the doorway 1m above the floor.
Given: the height and the width of the doorway is 4m and 3m respectively. Answered by Penny Nom. |
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Archimedes' formula for parabolic arches |
2009-01-23 |
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From La: Use calculus to verify Archimedes' formula for y=9-x^2. Prove Archimedes' formula for a general parabolic arch. Answered by Harley Weston. |
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A bridge is built in the shape of a parabolic arch |
2008-06-02 |
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From megan: A bridge is built in the shape of a parbolic arch. The bridge has a span of 192 feet and a maximum height of 30 feet. Find the height of the arch at 20 feet from its center. I need the equation and what to fill into the equation...please and thankyou! Answered by Penny Nom. |
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A parabolic arch |
2008-02-14 |
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From Angela: A parabolic arch has an equation of x^2 + 20y - 400 = 0 where x is measured in feet. How do I find the maximum height of the arch? Answered by Penny Nom. |
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parabolic arch |
2007-10-24 |
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From ABHILASH: How find parabolic arch perimeter. Answered by Harley Weston. |
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Parabolic arch |
2007-10-09 |
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From Nisa: A parabolic arch has a span of 120 feet and a maximum height of 25 feet. Choose suitable rectangular coordinate axes and find the equation of the parabola.
Then calculate the height of the arch at points 10 feet,20feet,and 40 feet from the center. Answered by Stephen La Rocque. |
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A parabolic arch |
2007-03-29 |
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From A student: I am trying to figure out how to work this problem as it doesn't have many
details.
The problem ask for an equation to satisfy a parabolic arch y = 16 - 0.25x^2
for y>=0.
Find the width w of the arch. Answered by Stephen La Rocque. |
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The width of an arch |
2007-03-28 |
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From Brad: A parabolic arch satisfies the equation y= 16 - 0.25x^2 for y >= 0. Find the width w of the arch. Answered by Penny Nom. |
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A roadway over a river |
2007-03-12 |
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From Taranjeet: My teacher has given us bridge with only one measurement. From the river to the roadway is 50 metres in length (vertically) The question he wants us to find out is. What is the distance between the vertical supports. He has said that: At a horizontal distance of 'x' metres from the foot of the arch the height of the arch, the height of the arch above the river 'h' metres is given by: h=-1/40(x squared) = 3x I don't understand how to find the distance between the support beams. Thank you Answered by Penny Nom. |
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Can the trailer safely pass under the bridge? |
2007-01-02 |
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From Jim: A truck hauling a double-wide trailer needs to pass under a parabolic-arched bridge en route or take a 50 mile detour. The trailer is 14 feet high and 15 feet wide. The arch supporting the bridge at this underpass is 18 feet high at the center and 40 feet wide at the base. Can the trailer safely pass under the bridge? Answered by Stephen La Rocque. |
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A fountain of water jets forms parabolic arches |
2006-05-03 |
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From Jennifer: Let's say in you have a fountain and the water jets form parabolic arches. The center of the fountain, being the origin of the coordinate system, it is elevated 5 feet off the ground, . The equation formed the water arch is y= -x2+4x, what is the radius of the basin needed to catch the water at ground level? Answered by Stephen La Rocque. |
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A parabolic arch |
2006-05-02 |
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From Mike: A bridge over a river is supported by a parabolic arch...arch is 200 m wide at water level...the maximum height of the arch is 80 m..what is the height of the arch measured from a point on the water 40m from the center of the arch? Answered by Stephen La Rocque. |
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A parabolic arch |
2004-01-19 |
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From Teresa and Robyn: A bridge over a river is supported by a parabolic arch...arch is 200 m wide at water level...the maximum height of the arch is 80 m..what is the height of the arch measured from a point on the water 40m from the centre of the arch Answered by Penny Nom. |
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