16 items are filed under this topic.
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A schedule for 8 golfers over 5 days |
2015-11-04 |
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From Ged: Hope you can help with the following to save next years arguments !
Schedule for 8 golfers playing as pairs in 2 X 4 balls on 5 days.
No player to pair same player more than once and to have played with each player
In the 4 ball.
Thanks. Answered by Victoria West. |
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8 golfers playing 5 round |
2015-06-11 |
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From Simon: We have 8 golfers playing 5 rounds, and want to make the pairings as even as possible (ie all play against everyone else)
2 of the players however must play together each day - due to a buggy being required.
If anyone has a formula to work this out I'd be appreciated Answered by Victoria West. |
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16 golfers over 15 weeks |
2014-07-11 |
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From Steve: I need a schedule for 16 golfers over 15 weeks, where each golfer is paired with a different golfer each week and plays 4 matches per week against 4 different pairs (each pair does not have to play each week) Answered by Penny Nom. |
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13 golfers in groupings of 4, 3, 3 and 3 |
2014-03-26 |
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From Lennart: How can I organise 13 players playing in groupings of 4,3,3,3 for 3 rounds of golf in a way that all play with all others but a minimum of times with the same players(?)If possible, nobody should play in the 4 ball more than once. I would be grateful for an answer/proposal! Thank you, LR Answered by Victoria West. |
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6 golfers in threesomes |
2013-09-04 |
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From Gregg: We have 6 golfers playing in threesomes for three rounds of golf. I would like each golfer to play equally with the other 5. How can this be done. Answered by Victoria West. |
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A schedule for 18 golfers |
2013-08-29 |
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From Brian: After searching the data base which helped me solve at least 3 other issues I have one more un answered question. I have 18 golfers split into 6 threesomes for 4 days of golf. What is my best option for a schedule mixing them all up as much as possible over the course of the 4 days Answered by Victoria West. |
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8 golfers playing 8 games |
2013-07-03 |
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From Johan: We have 8 golfers playing 8 games, and we want to schedule them so that they play together equal amount of times, or as close as you can get to that.
They will be playing in two four balls each day.
Anyone sorted this one out yet, I will really appreciate a solution?
Thanks
Johan Answered by Victoria West. |
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13 golfers playing 5 rounds |
2013-07-03 |
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From Alan: i have 13 golfers playing 5 rounds. want everyone to play together at least once. Answered by Victoria West. |
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13 golfers |
2013-07-02 |
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From James: 13 golfers playing in 4 groups [4,3,3,3 per group] for four rounds.
Can it be scheduled so that no two people play together more than twice? Answered by Victoria West. |
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16 golfers, 4 rounds |
2012-06-04 |
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From Gerry: 16 golfers, 4 rounds - best pairings so that everyone plays with each other at least once. Answered by Harley Weston. |
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16 golfers |
2012-04-20 |
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From steve: i have 16 golfers, 4 in "A" flight , 4 in "B" flight , 4 in "C" and 4 in "D"
We are playing 4 rounds (4 teams of 4) and every group must have a player from the A B C an D
flight, and in no round may 2 people have already played together! Answered by Victoria West. |
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15 golfers 3 rounds fivesomes |
2009-12-23 |
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From Dewey: I have 15 golfers playing 3 rounds of golf. We will be playing in fivesomes. Any formula that has everyone playing with a different person each round?
Thank you.
Dewey Answered by Robert Dawson. |
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Twelve golfers |
2009-06-26 |
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From Fred: Hello-
There are twelve golfers in 3 foursomes for three days. Is there a
combination of four man foursomes that allow for no duplicates? In
other words, is there a formula to insure the greatest amount of
variety in the foursomes. Looking at it math like you have
1,2,3,4,5,6,7,8,9,10,11,12 grouped into four numbers each for three
days. So if your have the first day 1,2,3,4 in one group, 5,6,7,8 in
the second and 9,10,11,12 in the third what can you do for the next
two days to have the fewest duplicates or have the greatest variety
in the foursomes?
Thanks Answered by Karen Meagher and Victoria West. |
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A golf outing for 16 golfers |
2005-08-05 |
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From Bob: I have a golf outing fast approaching and I’m having a problem matching the golfers so that everyone plays a round of golf with every other golfer in the group.
My problem is this: I have 16 golfers playing 5 rounds of golf. I would like a different foursome for every round of golf, that is each round (5 total) an individual is playing with 3 other players he hasn’t played with as of yet. Can you crunch the numbers and get back to me?
The way I see it, we have 20 combinations (5 rounds x 4 golfers) with numbers 1 thru 16. Answered by Chris Fisher. |
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20 Golfers |
2004-10-26 |
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From Ian: I have 20 golfers playing over 6 days I would like to schedule all 20 golfers in 5 groups of 4 on each day here is the catch.... I would like each player to play with each other once during the 6 days. Answered by Chris Fisher. |
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A schedule for 24 golfers |
2002-05-25 |
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From John: I am working on a schedule for 24 golfers. 6 groups of 4. I have 8 golf days (twice per week for a month). Ideally, I would like to schedule all 24 golfers in 6 different groups of 4 on each day. Here is the catch.....no golfer in any group can be grouped togther more than once. Every group of 4 each day will have 4 new golfers that have never played together before. Is this possible? Answered by Chris Fisher. |
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